Auto Control l – Lab Part A ReportHongzhi Yu a1657200INTRODUCTIONUse Matlab and Simulink to study the modelling facilities; the poles and zeros of open loop transfer function; the time response of control systems. RESULTS The open-loop transfer function is:Gol= 62.36—————————————–Continuous-time transfer function is:S^3+11.75s^2+17.55sThe poles are: 0, -10.0000, and -1.7548.There are no zeros.The closed-loop transfer function is:62.36——————————————–Continuous-time transfer function is:S^3+11.75s^2+17.55s+62.36The poles are: -10.6573, -0.5488+2.3560i, and -0.5488-2.3560iThere are no zeros.DISCUSSIONThe follow steps shows the explanation of the task.Step 1: Clear any existing variables in memory.Step 2: Input all conditions and constants.Step 3: Display the open-loop transfer function and the open-loop poles and zeros.Step 4: Calculate the closed-loop transfer function with unity proportional gain and feedback.Step 5: Show the values of open-loop poles and zero.
Step 6: The closed-loop poles and zeros figure-1. [pic 1] Fig.1 Step 7: The closed-loop step response figure-2.[pic 2] Fig.2Step 8: Vary the proportional gain (K) from 0.1 to 1.0 in 0.1 increments (Table-1). Show in figure-3. Choose the value gain (K)= 0.2 because the rise time is short and the peak response is low which means the airplane can rise in short time and keep stable will flying.[pic 3] Table 1[pic 4] Fig.3Step 9: Build a Simulink model of the plane roll control system figure-4. [pic 5] Fig.4Step 10: Run the Simulink model and compare the scope results figure-5.[pic 6] Fig.5As show in Fig.5, the diagram of Y(s) is similar to the closed-loop diagram in Fig.3. Start from 0 and constant at 1. The different is the diagram between 0 second and 1 second.