Chemistry – Course Note – Yanis Zeng
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Chemistry 11 Assignment 2 Total 25 marks[pic 1]Please make sure you highlight your final answer. Failure to do so will result in one mark taken off.Part 1 For the next questions, clearly show all the steps in solving the problems.  0.5 marks will be deducted for each time there is a significant figure error or appropriate units are not used!1.  What is the molar mass (to the nearest tenth of a gram/mole) of each of the following (2 marks)a. KClK: 1 x 39.1 = 39.1Cl: 1 x 35.5 = 35.5 39.1 + 35.5 = 74.6 g/molb. Al2(SO4)3Al: 2 x 27.0 = 54.0S: 3 x 32.1 = 96.3O: 12 x 16.0 = 19296.3 + 54.0 + 192 = 342g/mol2.  Convert the following mass into moles (1 mark)   19.5 grams of Al(OH)3Al: 1 x 27.0 = 27.0O: 3 x 16.0 = 48.0H: 3 x 1.0 = 3.027.0 + 48.0 + 3.0 = 78.019.5 grams Al(OH)3 x 1 mole / 78.0 grams Al(OH)3 =  0.250 mol Al(OH)33.  Convert the following moles into masses (1 mark)    2.00 moles of N22.00 moles x 28.0 g / 1 mole =56.0g N24. How many molecules are present in 1.5 moles of NaCl? (1 mark)1.5 moles NaCl x 6.02 x 10 ^23 molec NaCl/ 1 mole NaCl = 9.0 x 10^23 molec NaCl5.  How many atoms of chlorine are in 19.0 grams of MgCl2? (1 mark)Mg: 1 x 24.31 = 24.31Cl: 2 x 35.45 = 70.924.31 + 70.9 = 95.21       95.2 g/mol[pic 2]19.0 g MgCl2 x 1 mol MgCl2 /95.2 g Mg Cl2 x 6.02 x 10^23 molec/ 1 mol x 2 atoms/ 1 molec = 2.40 x 10 ^23 atoms6.  What is the volume of 2.60 moles of CO2(g) at STP? (1 mark)2.60 mol CO2 x 22.4 L CO2 / 1 mol CO2 = 58.24 L CO2         58.2 L CO2[pic 3]7.  What is the mass of 50.0 L of O2(g) at STP?  (1 mark)50.0 L O2 x 1 mol O2 / 22.4 L O2 x 15.99 g O2  / 1 mol O2 =35.7 g O28.  What is the percent composition of chlorine in PCl5?  (1 mark)Cl: 5 x 35.45= 177.25P: 1 x 30.97 = 30.97177.25 + 30.97 = 208.22         Cl: 177.25/208.22 x 100% = 85.13 %        The percent composition of Chlorine is 85.13 %        9.  Steven analyzed a compound and found it to be 52.7% Potassium and 47.3% Chlorine.   He determined the empirical formula to be …    (1 mark)52.7 g K x 1 mole K / 39.1 g k = 1.35 mol K/ 1.33 ≈ 147.3 g Cl x 1 mole Cl/ 35.45 g Cl = 1.33 mol Cl/1.33 = 1Empirical formula: KCl10.  If the empirical formula of a compound is CH2 and its molar mass is 70.0, then what is its molecular formula? (1 mark)12.0 C + 2 x 1.0 H = 14.0g/mol70.0 g/mol ÷ 14.0g/mol = 5 5 x CH2 = C5H1011.  If 0.30 mol NaCl goes into a solution with 4.00L water, the molarity of NaCl is (2 marks)M = n / V  M= 0.30 mol / 4.00LM= 0.0750 mol/ L 12.  If 100.0 ml water is added to 150.0 ml of a 2.00M HCl solution, the new molarity of HCl is (2 marks)150.0 mL x 1 L/ 1000 mL = 0.1500L100.0Ml x 1L/1000mL= 0.1000L n = mv

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(2017, 10). Chemistry. EssaysForStudent.com. Retrieved 10, 2017, from
“Chemistry” EssaysForStudent.com. 10 2017. 2017. 10 2017 < "Chemistry." EssaysForStudent.com. EssaysForStudent.com, 10 2017. Web. 10 2017. < "Chemistry." EssaysForStudent.com. 10, 2017. Accessed 10, 2017. Essay Preview By: Yanis Zeng Submitted: October 31, 2017 Essay Length: 908 Words / 4 Pages Paper type: Course Note Views: 338 Report this essay Tweet Related Essays Brief Historical Development and Contributions of Chemistry for Modern Civilization Brief Historical Development and Contributions of Chemistry for Modern Civilization Introduction: As defined by Oxford Dictionary, Chemistry is the scientific study of the structure of 847 Words  |  4 Pages Organic Chemistry Homologous Series: An homologous series is a set of compounds whose components differ by a single repeating functional group. In the case of (straight chain) 262 Words  |  2 Pages Multistep Synthesis Chemistry Experiment Multistep Synthesis of Tetraphenylcyclopentadienone In this laboratory experiment a synthesis was performed through several separate steps. The purpose of the experiment was to synthesize tetraphenylcyclopentadienone 1,813 Words  |  8 Pages Chemistry Independent Study Chemistry Independent Study: Gas Laws Gas Laws Since the days of Aristotle, all substances have been classified into one of three physical states. A substance 2,517 Words  |  11 Pages If We Had Known About Green Chemistry in 1951, How Would Things Be Different Today? If We Had Known About Green Chemistry In 1951, How Would Things Be Different Today? Green Chemistry is the making of chemical products that reduces 716 Words  |  3 Pages Similar Topics Chemistry Planning Designing Lab Chemistry Study Guide Get Access to 89,000+ Essays and Term Papers Join 209,000+ Other Students High Quality Essays and Documents Sign up © 2008–2020 EssaysForStudent.comFree Essays, Book Reports, Term Papers and Research Papers Essays Sign up Sign in Contact us Site Map Privacy Policy Terms of Service Facebook Twitter

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Homologous Series And Mol Al. (April 3, 2021). Retrieved from https://www.freeessays.education/homologous-series-and-mol-al-essay/