Centripetal Force
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Centripetal Force
Nicholas Dadufalza
Alexis and Austin
Period 6
January 19, 2012
Objectives:
1. To find out how centripetal force is related to velocity, mass, and radius of the circular path.
2. To determine the m/r ratio for an object undergoing circular motion
Data:
Suspended Mass (kg)
Suspended Weight (N)
Time for 30 Rev. (s)
Time for One Rev. (s)
Circumference (m)
Speed (m/s)
.0553
.10578
1.037
22.05
.15535
1.522
17.94
.20526
2.012
15.42
12.22
.25524
2.501
13.69
13.49
Measured Mass of Stopper: _______0.01377______ kg
Measured Radius of Circular Path: 1.00 m
Measured Mass/Radius Ratio: _____0.01377_____ kg/m
Data Treatment:
Weight = (9.8m/s^2) x (Mass)
Weight = (9,8m/s^2) x (.0553kg) = .542N
Time for One Rev = (Time for 30 rev)/ (30 rev)
Time for One Rev = (29.1s)/(30 rev) = .97s
Circumference = 2ᴨ x radius
Circumference = 2 ᴨ x (1m) = 6.28m
Speed = distance traveled / time traveled
Speed = 6.28m/.97s = 6.47m/s
Centripetal Force = (mass x velocity^2 )/ radius
Centripetal Force = .01377kg x velocity^2 /1m = .01377kg/m x velocity^2
Centripetal Force = (mass x velocity^2 )/ radius
Centripetal Force = (5kg x( 5m/s)^2)/5m = 25 N
Centripetal Force = (mass x velocity^2)/ radius
25N = (10kg x velocity^2)/5m
125N*m = 10 kg x velocity^2
12.5m^2/s^2 = velocity^2
3.5 m/s = velocity
25N = (5kg x velocity^2)/10m
250N*m = 5kg x velocity^2
50 m^2/s^2 = velocity^2
7.1m.s = velocity
Percentage of Error = |accepted value – experimental value| / accepted value x 100%
Discussion:
1.Plot a graph of centripetal force (suspended weight) versus speed. Describe the resulting curve. What function of speed appears to vary directly with force?
As the velocity increases on the graph, the centripetal force increases. Since one increases as the other increases, it is a direct relationship; therefore, velocity and centripetal force have a direct relationship.
2.Plot the graph which you think will give a linear relationship (force versus some function of speed). According to this straight line, what function of speed varies directly with force (F ?) Does this support the form of the equation for centripetal force given in the text?
The square of velocity varies directly with force. This supports the form of the equation for centripetal force given in the text because there is a square of velocity in the equation. The square of velocity is also on the top which means that is directly proportional to the